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Add pauses

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prescientmoon 2025-03-21 13:05:31 +01:00
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\end{align*}
\end{definition}
\item The spectrum of this operator is a subset of $[0, \infty)$. We call it the \emph{spectrum} of the manifold.
\pause
\item The spectrum determines many things about the space (like its volume).
\item When two distinct (up to isomorphism) manifolds share a spectrum, they for an \emph{isospectral pair}.
\end{enumerate}
@ -32,6 +33,12 @@
\end{comment}
\begin{frame}{The silver lining}
\begin{tikzpicture}
\clip (0,0) rectangle (\paperwidth,\paperheight);
\fill[color=orange] (\paperwidth-10pt,0) rectangle (\paperwidth,\paperheight);
% Added
\fill[color=orange](0,0) rectangle (10pt,\paperheight);
\end{tikzpicture}
\begin{itemize}
\item Isospectral pairs are cool and all, but they cannot occur in dimension $3$.
\item We can thus attempt to infer the shape of our universe based on its spectrum.

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\caption{The prototypical example of a manifold a mug [13].}
\label{fig:mug-neighbourhoods}
\end{figure}
\pause
\begin{figure}[H]
\centering
@ -20,6 +21,7 @@
\begin{itemize}
\item $\so 4$ is isomorphic to the isometry group of $\S^3$.
\item Subgroups $\Gamma \leqslant \so 4$ define equivalence classes of orbits on $\S^3$ by the standard action of $\so 4$ on $\R^4$, i.e. $x \sim y$ iff $x = My$ for some $M \in \Gamma$.
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\item The obtain space is (\emph{sometimes}) a manifold. In particular, it is well defined and spherical for finite $\Gamma$.
\item This can be easily generalised to the $n$-sphere.
\end{itemize}
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\end{align*}
\end{definition}
\pause
In the $\S^3$ case, we denote $\lens p q \coloneq \lens p {(1, q)}$ for coprime $p, q \in \mathbb Z$.
\end{frame}